Question

plzz solve this!!! ​

Answer 1

Answer:

Step-by-step explanation:

a) hence √5 is a irrational number

let 2√3-3√5 is a rational number

2√3-3√5=a/b is rational number

3√5=2√3-a/b              "

√5=2√3b-a/3b            "

so √5 is a rational number

but we known that √5 is irrational number

so therefore√5 is a irrational number

B) g(x)=(x-2-√5)(x-2+√5)

          =(x-2)²-(√5)²

          = x² +4-4x-5

          = x²-4x-1

x²-4x-1 ÷ x^4+x³-15x²-29x-6

          =x²+5x+6

           =x²+3x+2x+6

           =x(x+3)2(x+3)

           = x=-3 and x=-2