Plzz solve this below question fast
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Step-by-step explanation:
in a triangle abc let AE be ⊥ BC and all sides of the triangle be a.
BD=1/3BC
BC=3BD
BE=CE=BC/2=a/2
AE=a√3/2
ED=a/6
In rt. trianglle ADE
AD²=AE²+ED²
=(a√3/2)²+(a/6)²
=3a²/4+a²/36
=27a²+a²/36
=28a²/36
=7a²/9
AD²=7a²/9
9AD²=7a²
9AD²=7AB²(as AB=a)
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See the attachment:-
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chavanchintu04:
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