Plzz solve this.........factorise 9(x+a)^2-4x^2
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Hi friend
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Your answer
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★ FACTORISATION
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![using \: identity \: = > a {}^{2} - b {}^{2} = (a + b)(a - b) \\ \\ 9(x + a) {}^{2} - 4x {}^{2} \\ \\ = > (3(x + a)) {}^{2} - (2x) {}^{2} \\ \\ = > (3(x + a) + 2x)((3(x + a) - 2x) \\ \\ = > (3x + 3a + 2x)(3x + 3a - 2x) \\ \\ = > (5x + 3 a)(x + 3a) using \: identity \: = > a {}^{2} - b {}^{2} = (a + b)(a - b) \\ \\ 9(x + a) {}^{2} - 4x {}^{2} \\ \\ = > (3(x + a)) {}^{2} - (2x) {}^{2} \\ \\ = > (3(x + a) + 2x)((3(x + a) - 2x) \\ \\ = > (3x + 3a + 2x)(3x + 3a - 2x) \\ \\ = > (5x + 3 a)(x + 3a)](https://tex.z-dn.net/?f=using+%5C%3A+identity+%5C%3A++%3D++%26gt%3B+a+%7B%7D%5E%7B2%7D++-+b+%7B%7D%5E%7B2%7D++%3D+%28a+%2B+b%29%28a+-+b%29+%5C%5C++%5C%5C+9%28x+%2B+a%29+%7B%7D%5E%7B2%7D++-+4x+%7B%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+%283%28x+%2B+a%29%29+%7B%7D%5E%7B2%7D++-+%282x%29+%7B%7D%5E%7B2%7D++%5C%5C++%5C%5C++%3D++%26gt%3B+%283%28x+%2B+a%29+%2B+2x%29%28%283%28x+%2B+a%29+-+2x%29+%5C%5C++%5C%5C++%3D++%26gt%3B+%283x+%2B+3a+%2B+2x%29%283x+%2B+3a+-+2x%29+%5C%5C++%5C%5C++%3D++%26gt%3B+%285x+%2B+3+a%29%28x+%2B+3a%29)
HOPE IT HELPS
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Your answer
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★ FACTORISATION
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HOPE IT HELPS
Answered by
0
9(x+a)^2-4x^2
[3(x+a)]^2-(2x)^2
(3x+3a)^2-(2x)^2
(3x+3a+2x) (3x+3a-2x)
[3(x+a)]^2-(2x)^2
(3x+3a)^2-(2x)^2
(3x+3a+2x) (3x+3a-2x)
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