Question

plzz solve this fast and PLZZZZZZZZZZ send the pic of the answer

Answer 1

X=0 SO SIMPLE WHEN YOU ADD 0 IN THE POSITION OF X YOU WILL GET THE ANSWER AS 0

Answer 2

${x}^{2} + 5x - ( {a}^{2} + a - 6) = 0$
Apply the quadratic formula,

$x = \frac{ - 5 \pm \sqrt{25 + 4( {a}^{2} + a - 6)} }{2} \\ x = \frac{ - 5 \pm \sqrt{25 + 4 {a}^{2} + 4a - 24} }{2} \\ x = \frac{ - 5 \pm \sqrt{4 {a}^{2} + 4a + 1} }{2} \\ x = \frac{ - 5 \pm \sqrt{(2a + 1) ^{2} } }{2} \\ x = \frac{ - 5 \pm {(2a + 1) } }{2} \\ x = a - 2 \\ \text {or} \\ x = - a - 3$