Question

plzz solve this...FAST PPPPllllllzzzzz

Answer 1

(1)

$= \ \textgreater \ (5 \sqrt{3} + 6 \sqrt{2} )(3 \sqrt{5} - 2 \sqrt{6} )$

$= \ \textgreater \ 5 \sqrt{3} * 3 \sqrt{5} - 5 \sqrt{3} * 2 \sqrt{6} + 6 \sqrt{2} * 3 \sqrt{5} - 6 \sqrt{2} * 2 \sqrt{6}$

$= \ \textgreater \ 15 \sqrt{15} - 30 \sqrt{2} + 18 \sqrt{10} - 24 \sqrt{3}$



(2)

We know that (a + b)^2 = a^2 + b^2 + 2ab.

$= \ \textgreater \ (5 \sqrt{5} - 3 \sqrt{2})^2$

$= \ \textgreater \ (5 \sqrt{5} )^2 + (3 \sqrt{2} )^2 - 2(5 \sqrt{5} )(3 \sqrt{2)}$

$= \ \textgreater \ 125 + 30 \sqrt{10} + 18$

$= \ \textgreater \ 30 \sqrt{10} + 143$



(3)

Given : (2x - 3y + 6z)^2

= > (2x - 3y + 6z)(2x - 3y + 6z)

= > 2x *2x - 2x * 3y + 2x * 6x - 2x * 3y - 3y * 3y - 3y * 6z + 2x * 6z - 3y * 6z + 6z * 6z


= > 4x^2 - 12xy + 24xz + 9y^2 - 36yz + 36z^2.



(4)

$= \ \textgreater \ (2 \sqrt{2} - \sqrt{3} )^3$

We know that (a - b)^3 = a^3 - 3a^2b + 3ab^2 - b^3.

$= \ \textgreater \ (2 \sqrt{2} )^3 - 3(2 \sqrt{2} )^2 \sqrt{3} + 3 * 2 \sqrt{2} ( \sqrt{3} )^2 - ( \sqrt{3} )^3$

$= \ \textgreater \ 16 \sqrt{2} - 24 \sqrt{3} + 18 \sqrt{2} - 3 \sqrt{3}$

$= \ \textgreater \ -27 \sqrt{3} + 34 \sqrt{2}$




Hope this helps!

Answer 2

Hi,

Please see the attached file!


Thanks