Question

plzz solve this guyzzzz ..I m always thankful to u plzz.solve by explanation and. step by step...​

Answer 1

Solution :

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Answer - 1) :

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⏭ Given:

✏ A scooterist travels a certain distance with speed of 50kmph and returns back at the starting point with a speed of 40kmph.

⏭ To Find:

• Average speed
• Average velocity

⏭ Concept:

✏ Average speed is defined as the ratio of total distance covered to the total time taken.

✏ Average velocity is defined as the ratio of total displacement to the total time taken.

⏭ Calculation:

• Average speed

$\mapsto \sf \: \tt{ \red{v_{av} = \dfrac{2 \times v_1 \times v_2}{v_1 + v_2}}} \\ \\ \mapsto \sf \: v_{av} = \dfrac{2 \times 50 \times 40}{50 + 40} \\ \\ \mapsto \sf \: v_{av} = \frac{4000}{90} \\ \\ \mapsto \: \boxed{ \tt{ \pink{ \large{av. \: speed = 44.44 \: kmph}}}}$

• Average velocity

$\implies \sf \: \red{displacement = zero} \\ \\ \because \sf \: \triangle{position} = zero \\ \\ \implies \: \boxed{ \tt{ \blue{ \large{av. \: velocity = zero}}}}$

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Answer - 2) :

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⏭ Given:

✏ A cyclist moves a distance of 30m from points A to B in a straight line towards east with a speed of 10mps.

✏ He then moves a distance of 40m from poinr B to C in north direction with a speed of 20mps.

✏ Please see the attachment for better understanding.

⏭ To Find:

• Average speed
• Average velocity

⏭ Calculation:

• Average speed

$\implies\sf \: av.speed = \dfrac{total \: distance}{total \: time}\\ \\ \implies\sf \: av.speed = \dfrac{30+40}{5} = \dfrac{70}{5} \\ \\ \implies \boxed{\tt{\large{\green{av.speed = 14 \: mps}}}}$

• Average velocity

$\mapsto\sf \: av.velocity = \dfrac{displacement}{time} \\ \\ \mapsto\sf \: av.velocity =\dfrac {50}{5}\\ \\ \mapsto \: \boxed{\tt{\large{\orange{av.velocity = 10\: mps}}}}\: \sf{(towards \: AC)}$

Answer 2

$\large \underline{ \blue{ \boxed{ \bf \green{Required \: Answer}}}}$