Question

plzz solve this problem and don't give me irrevelant replies otherwise I will report him/ her and give explaination​

Answer 1

Answer:

60°

Step-by-step explanation:

Given,

ABCD is a quadrilateral.

∠C=70 °, ∠D=50 °

So,

∠A+∠B+∠C+∠D=360 °

(A+B)=360° − (C+D)

⇒(A+B)=360° − (70°+50°)

⇒(A+B)=360°−120°

⇒(A+B)=240 °

According to given question,

∠OAB= ∠A/2

∠OAB= ∠B/2

Now,

∠OAB+∠OBA= (∠A+∠B)/2 =120°

⇒∠AOB+120°=180°

⇒∠AOB=180°−120°

⇒∠AOB=60°

Hope this works :)