plzz solve this problem I 'm not getting it
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Anonymous:
prove that the problem is =1
hey its too blury !
everyone is writing questions
pls write nicely i am confused whether it is x^a or x^b
It is '(x^b/x^a)^c' I Think (not 'x') then you'll get the answer...
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Greetings,
The answer to your question is typed below↓
______________________________________________
x^[a(b-c)] / x^[b(a-c)] ÷ (x^b/x^a)^c = 1
L.H.S.: [You'd better transfer this to a note to understand better>]
As bases are same in numerator and denominator, a power when taken to the numerator from the denominator is subtracted.
⇒ x^(ab-ac)/x^(ab - bc) ÷ (x^(b-a))^c
when a power is raised to another power, both powers are multiplied.
⇒ x^[(ab-ac) - (ab-bc)] / x^(bc-ac)
⇒ x^(bc-ac) / x^(bc-ac) = 1 {numerator and denominator cancel out.}
Proved....
______________________________________________
P.S.:Enjoy;)
The answer to your question is typed below↓
______________________________________________
x^[a(b-c)] / x^[b(a-c)] ÷ (x^b/x^a)^c = 1
L.H.S.: [You'd better transfer this to a note to understand better>]
As bases are same in numerator and denominator, a power when taken to the numerator from the denominator is subtracted.
⇒ x^(ab-ac)/x^(ab - bc) ÷ (x^(b-a))^c
when a power is raised to another power, both powers are multiplied.
⇒ x^[(ab-ac) - (ab-bc)] / x^(bc-ac)
⇒ x^(bc-ac) / x^(bc-ac) = 1 {numerator and denominator cancel out.}
Proved....
______________________________________________
P.S.:Enjoy;)
Thanks bruh
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