Question

Plzz solve this problem..
I will mark the correct answer as the Brainliest...​

Answer 1

Answer:

Solution

According to the question

Triangle ABC ~ triangle DEF

Hence

$\frac{ab}{de} = \frac{bc}{ef} = \frac{ca}{fd}$

so

$= = > \frac{2x - 1}{18} = \frac{3x + 2}{3x + 9} = \frac{3x}{6x}$

Now we take

$= = > \frac{2x - 1}{18} = \frac{3x}{6x}$

$we \: have \: already \: \frac{2x - 1}{18} = \frac{3x}{6x} = \frac{1}{2}$

$= = > 4x - 2 = 18 \: or \: x - 5$

$therfore \: ab \: = 2 \times 5 - 1 = 9$

$= = > bc \: = 2 \times 5 + 2 = 12 \\ = = > ca = 3 \times 5 = 15$

$= = > de = 18 \\ = = > ef = 3 \times 5 + 9 = 24 \\ = = > fd = 6 \times 5 = 30$

Therefore AB= 9 , Bc = 12 , FD = 30 , EF = 24

Hope it is helpful for you