Question

plzz...solve this problem. ..in a easiest way

Answer 1

Hope it will help you

Answer 2

нєу тнєяє ιѕ αиѕωєя !!!
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ι нσρє уσυ нєℓρ !!!
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мαяк мє вяαιи ℓιѕт fяιєи∂ѕ !!!
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Let x any positive integer , then it is of the form 4m, 4m+1or4m+2

When x=4m

χ^2 = 16м^2 = 4(4м)^2= 4q ωнєяє = 4q

when x=4m+2

χ^2 = (4м +1 )^2 = 16м^2+16м+4= 4(4м^2+4м+1)= 4q ωнєяє q = 4м^2 + 4м+1

When x=4m+1

χ^2 = (4м+ 1 )^2 = 16м^2 +8м +1 =σ = 4 ( 4 м^2 + 2м ) +1 = 4q+1

Hence,the square of any positive integer is either of the form 4q or 4q + 1 for some integer q.