Question

PLZZ SOLVE THIS PRPBLEM... ITS CLASS 10.. ICSE QSTN... ​

Answer 1

Answer:

xyis 680 its answer

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Answer 2

Let the original cost of each book = x

Total Books brought for 960 = 960/x

Now,

The cost of each book = Rs. (x - 8)

Number of books bought for 960 = 960/(x - 8)

From the given information, we have:

960/(x - 8) - 960/x = 4

=> x^2 - 8x = 1920

=> x^2 - 8x - 1920 = 0

=> x^2 - 48x + 40x - 1920 = 0

=> x(x - 48) + 40(x - 48) = 0

=> x = 48 or x = -40

But x cannot be negative.

∴ x = 48.

The original cost of each book = 48.

Hope it helps!.