plzz solve this ques.
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sizaB:
20 degree
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Answered by
1
angle ACB = angle ADB = 40°
In triangle PDB
angle PBD = 20° ( by angle sum property )
angle CBD = angle PBD = 20°
hope it helps. . . . mark as brainlliest answer
In triangle PDB
angle PBD = 20° ( by angle sum property )
angle CBD = angle PBD = 20°
hope it helps. . . . mark as brainlliest answer
mark as brainlliest answer
Answered by
0
answer is 30°
because look the ∆ PBD it is a isoscele triangle and we know that the radius of a circle is alsways equal by the condition that is a isoscele triangle
so the angle <CBD is 30°
because look the ∆ PBD it is a isoscele triangle and we know that the radius of a circle is alsways equal by the condition that is a isoscele triangle
so the angle <CBD is 30°
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