Question

plzz solve this question

Answer 1

Answer:

Step-by-step explanation:

Let ABCD be a parallelogram and L extended to prove that

Let us first show that in triangle PCD and BPL, the angle of DPC and BPL are same as they are vertically opposite to each other.

The angle C = B, as they are alternate angle, therefore it shows that triangle PCD and BPL are similar in nature, therefore sides DP = PL and DC = BL.

Hence Proved

Now it can be said that as AB = DC, due to parallel sides of a parallelogram, it is known that  

Hence, Proved

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Answer 2

Step-by-step explanation:

(1)IN ∆DPC and ∆PLB

DPC = LPB. (vertically opp.)

PDC = PLB. ( alt int. angles)

∆ DPC~∆LPB. (AA similarity)

DP:PL= PL:BP

(2)In ∆DLA and ∆PLB

DL:DP=AL:AB. (BY Thales theorem)

DL:DP= AL:DC. ( AB=DC)

(opp.sides of a

parallelogram)

Hence proved