Question

plzz solve this question ​

Answer 1

Answer:

$\frac{ - 33}{8} \div ( \frac{ - 11}{2} ) \\ \\ = \frac{ - 33}{8} \times \frac{2}{ - 11} \\ \\ \\ = \frac{ - 33}{ - 44} \\ \\ = \frac{3}{4}$

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Answer 2

Question :

By what number should $\tt{ \dfrac{-33}{8}}$ be divided to get $\tt{ \dfrac{-11}{2}}$

Answer :

According to the question we have been asked that by what number should -33/8 be divided in order to get -11/2.

$\tt{ Let \: us \: consider \: the \: number \: to \: be \: divided \: as \: x}$

$\tt{ So \: according\: to \:the \:question :}$

$\tt{ \dfrac{-33}{8} \div x \implies \dfrac{-11}{2}}$

To find the value of x we will transpose $\tt{ \dfrac{-11}{2}}$ to the other side . So we get :

$\tt{ x \implies \dfrac{-33}{8} \div \dfrac{-11}{2}}$

We know that when we transpose a numerical ; the sign changes .

In the case of division one of the values gets reciprocated ; so we get :

$\tt{ x \implies \dfrac{-33}{8} \times \dfrac{2}{-11}}$

$\tt{ x \implies \cancel{\dfrac{-33}{8} \times \dfrac{2}{-11}}}$

$\large{\boxed{\tt{ x \implies \dfrac{3}{4}}}}$

And hence the same is to be divided by (-33/8) to get (-11/2)