plzz solve this question
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Step-by-step explanation:
i) ∠DAC + ∠BCD = 180°(sum of opposite angles of a cyclic quadrilateral is 180°)
105°+∠BCD = 180°
∠BCD = 75°
ii) AB and DC are parallel and DA is a transversal then,
∠DAC + ∠ADC = 180°(sum of interior angles on the same side of the transversal is 180°)
105°+∠ADC = 180°
∠ADC = 75°
iii) You can either solve using method used in (i) or (ii)
∠ABC+∠ADC = 180°(sum of opposite angles of a cyclic quadrilateral is 180°)
∠ABC+∠BCD= 180°(sum of interior angles on the same side of the transversal is 180°)
∠ABC = 105°
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