Question

plzz solve this question

Answer 1

$x(t) = 3t {}^{2} - 2t + 5$

Position at t = 2s is given by

$x(2) = 3(2) {}^{2} - 2(2) + 5$

$x(2) = 12 - 4 + 5$

$x(2) = 13$

Velocity is given by differentiation of x (t)

$v(t) = d(x(t)) \div dt$

$= d(3t {}^{2} - 2t + 5) \div dt$

$v(t)= 6t - 2$

Acceleration is differentiation of v (t)

which is 6