Question

Plzz solve this question

Answer 1

$= > - I _{1} + 0 \times I _{XY} + 3I _{3} = 0 \\ \\ = > I _{1} = 3I _{2} \: \: \: ...[Eq _{1}]$
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$= > - 2(I _{1} - I _{XY} ) + 4(I _{2} + I _{XY}) = 0 \\ \\ = > 2I _{1} - 4I _{2} = 6I _{XY} \: \: \: ..[Eq _{2}]$
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$= > V _{AB} - 1 \times I _{1} - 2(I _{1} - I _{XY}) = 0 \\ \\ = > 50 = I _{1} + 2(I _{1} - I _{XY}) \\ \\ = > 50 = 3I _{1} - 2I _{XY} \: \: \: \: ...[Eq _{3}]$
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» Eq[1] multiply by 2 :-

$= > 2I _{1} = 6I _{2} \: \: \: ...[Eq _{4}]$
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» By Eq[2] - Eq[4]

$= > - 4I _{2} = 6I _{XY} - 6I _{2} \\ \\ = > 2I _{2} = 6I _{XY} \\ \\ = > I _{2} = 3I _{XY} \: \: \: ...[Eq _{5}]$
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» By Eq[5] , Eq[4] and Eq[3]

$= > 50 = 3I _{1} - 2I _{XY} \\ \\ = > 50 = 3(3I _{2}) - 2I _{XY} \\ \\ = > 50 = 9(3I _{XY}) - 2I _{XY} \\ \\ = > 50 = 27I _{XY} - 2I _{XY} \\ \\ = > 50 = 25I _{XY} \\ \\ = > I _{XY} = 2 \: A$
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