Question

plzz solve this question ???

Answer 1

$\sin(3 \alpha ) = \cos( \alpha - 6) \\ \sin(3 \alpha ) = \sin( \frac{\pi}{2} - \alpha + 6 ) \\ 3 \alpha = \frac{\pi}{2 } - \alpha + 6 \\ 4 \alpha = \frac{\pi}{2} + 6 \\ \alpha = \frac{\pi}{8} + 6$


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