Question

plzz solve this question​

Answer 1

∠BDA and ∠BDC are linear pairs. ∴ ∠BDC=90°

Also ∠BED and ∠CED are linear pairs. ∴ ∠BED = 90°

Consider ΔBDC and ΔBED.

∠BDC = ∠BED = 90°

∠DBC = ∠DBE    (common)

∴ ΔBDC ~ ΔBED.

$\therefore\ \frac{DE}{BE}=\frac{DC}{BD} \\ \\ \\ DE \times BD = DC \times BE$

Hence showed!

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