Math, asked by niharika2678, 1 year ago

plzz solve this question​

Attachments:

Answers

Answered by rahul077
2

here is the answer

if a=√5+√2/√5-2. b= √5-√5/√5+√2

A²-b²

=[2-√5/2+√5]²-[2+√5/2-√5]²

=[2-√5]²/[2+√5]²-[2+√5]²/[2-√5]²

=[4+5-4√5/4+5+4√5]-[4+5+4√5/4+5-4√5]²

=[9-4√5/9+4√5]-[9+4√5/9-4√5]

=[9-4√5]²-[9+4√5]²/9²-[4√5]²

=81+80-72√5-81-80-72√5/81-80

=-144√5/1

=-144√5

3a2+4ab-3b2=4+56√10/3

a = [√5 + √2 ]/ [√5 - √2] and b = [√5 - √2] / [√5 + √2] on rationalizing a and b , we get a = [√5 + √2 ]/ [√5 - √2] ×[√5 + √2] / [√5 + √2] a = (7+2√10)/3 similarly b = [√5 - √2] / [√5 + √2] × [√5 - √2 ]/ [√5 - √2] b = (7 - 2√10)/3 so, 3a2 + 4ab – 3b2 = 3(a2 – b2) +4ab = 3 [ {(7+2√10)/3}2 – {(7- 2√10)/3}2 ] +4 [ (7+2√10)/3 × (7- 2√10)/3 ] = 3 [ (49 + 40 +28√10)/9 - (49+40-28√10)/9 ] + 4 [ (49 -40)/9 ] = 3 [ 56√10/9] + 4 = 56√10/3 +4 so, 3a2 + 4ab – 3b2 =4 + (56/3)√10

marke it brainlist


vivek4287: hii
Answered by Needthat
1

check the attachment

hope it helps

Attachments:

adityapatil16: hii
Similar questions