Question

plzz solve this question..

anyone​

Answer 1

Step-by-step explanation:

Previous length = l

Area = A

→Resiatance = rho ×L/A= 1 ....(1)

Since , the new length is 2l but volume(V) of the conductor is constant

→V = 2l× New area of cross section .

→V/2l= New area of cross section .

→A/2 is new area of cross section .

→New resistance = rho × 2l/(A/2)

=4{rho ×l/A}= 4 ohm {using(1)}