Question

plzz solve this question
for JEE aspirants
IMPORTANT QUESTION
CLASS 11TH

PLZZZ DON'T send wrong answer
BEST ANSWER WOULD BE MARKED AS BRANLIEST
chapter=quadratic equation​

Answer 1

Heyo Mate!!!!

Here's Your Answer!!!

x³+0x²+4x+1=0

Let Roots be A,B,C

so Sum Of Roots

• =A+B+C=-b/a=0

Now Sum Of PRODUCT OF Two Zeroes

• AB+BC+AC=c/a=4/1=4

Now The Product of Zeroes

• ABC=-d/a=-1/1=-1

Now we have to Find

(1/A+B)+(1/B+C)+(1/C+A)

LCM=(ABC)²

= (B+C)(C+A)+(A+B)(C+A)+(A+B)(B+C)

(ABC)²

= BC+C²+AB+AC+AC+A²+BC+AB+AB+AC+B²+BC

(ABC)²

=A²+B²+C²+3(AB+BC+AC)

(ABC)²

=[(A+B+C)²-2(AB+BC+AC]+3(AB+BC+AC)

(ABC)²

=(0²)+[AB+BC+AC]

(-1)²

=[4]

Therefore 3)Option is correct

Answer is 4

Hope it's Correct

Thank You

Regards ☺️ ✌️

Answer 2

Answer:

Option3 - 4.................