Question

plzz solve this question if anyone knows.....​

Answer 1

Answer:

=${4}^{x} - 3( {2}^{x + 3} ) + 128 = 0$

=${2}^{2x} - 3 \times {2}^{x} \times {2}^{3} + 128 = 0$

=$( { {2}^{x} })^{2} - 24 \times {2}^{x} + 128 = 0$

let 2^x =y

${y}^{2} - 24y + 128 = 0$

${y}^{2} - 16y - 8y + 128 = 0$

y(y-16) -8(y-16)=0

(y-16)(y-8)=0

Y=8 or Y =16

Option D is correct

Step-by-step explanation:

Hope it will help you

Jai Hind