Question

plzz solve this question step by step...

question-
${x}^{2} + \frac{1}{9 {x}^{2} } = \frac{25}{36} \: then \: {x}^{3} + \frac{1}{27 {x}^{3} } = what \: \\ also \: x > 0$
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Answer 1

x^2 + 1/9 x^2

( x+ 1/3x)^2 - 2/3 = 25/36

= 25/36 + 2/3

= 25 + 24)/36 = 49/36

x+ 1/3x = +- 7/6

X>0

so neglect -7/6

Now

x^3 + 1/27x^3

( x+ 1/3x)^3 - 3/27 ( x+ 1/3x)

(7/6)^3 - 1/9. × 7/6

7/6 ( 49/36. - 1/9)

7/6 ( 49 - 4)/36

7/6. × 45/36

315/216

1.45