plzz solve this question with explaination
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Since it yields phenyl hydrazone. This indicates presence of corbonyl group.
It gives negative response to the Iodoform test. This indicates absence of methyl keto group.
Hence, n-amyl alcohol and 2- pentanone are ruled out.
Now, it gives negative response to Tollen's rule.
This indicates absence of aldehyde group.
Hence, pentanal is ruled out.
It produces n-pentane on reduction. This indicates presence of 5-carbon backbone.
Therefore, 'X' must be 3- pentanone.
Hope this helps!
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