Chemistry, asked by nidhigautam57, 11 months ago

plzz solve this question with explaination ​

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Answered by anushkabhagat30
1

Answer:

Since it yields phenyl hydrazone. This indicates presence of corbonyl group.

It gives negative response to the Iodoform test. This indicates absence of methyl keto group.

Hence, n-amyl alcohol and 2- pentanone are ruled out.

Now, it gives negative response to Tollen's rule.

This indicates absence of aldehyde group.

Hence, pentanal is ruled out.

It produces n-pentane on reduction. This indicates presence of 5-carbon backbone.

Therefore, 'X' must be 3- pentanone.

Hope this helps!

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