Question

plzz solve this question with solution plzzz because tomorrow is my exam
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Answer 1

Answer:

ans i) if two supplementry angles are of the ratio 3:2 then let,

their ratio be 3x and 2x

Now,

3x + 2x = 180° (supplementary angles)

5x. = 180°

x. = 180°/ 5

x = 36°

hence the angles are 3x = 3 × 36 = 108°

and 2x = 2 × 36 = 72°

ans ii) Given,

one of the supplementary angle is 3 times the value of the other...

therefore let the angles be,

3x and x

now,

3x + x = 180°

4x = 180°

x = 180°/4

x = 45°

hence the angles are 3x = 3 × 45° = 135°

and x = 45°

Step-by-step explanation:

oh...sry.. i wrote the steps above in the ans section..well hope it's ok for you.. anyways best of luck of the exam...go crack it!