Plzz solve this question with steps. Plzz do it fast. Need it.
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Answer:
sinA=-2√6/5
cosA=± √1-sin^2A
=± √1- (-2√6/5)^2
=± √1-24/25
=±√25-24/25
=±√1/25
=± 1/5
A lies in the third quadrant
cosA=-1/5
similarly
tanA=sinA/cosA
-2√6/5
= ----------
-1/5
= 2√6
again
cotA= cosA/sinA
-1/5
= ---------
- 2√6/5
=1/2√6
again
secA= 1/cosA
= 1/-1/5
= -5
again
cosecA=1/sinA
=1/-2√6/5
=-5/2√6
I hope you understand
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