Question

plzz solve this sum as soon as possible......​

Answer 1

Answer:

sides are 10m , 24 m , 26 m

Step-by-step explanation:

let shortest side be x

therefore hypotenuse = 6+(2x)

3rd side = hypotenuse-2 = (6+2x)-2 = 2x + 4

using Pythagoras theorem,

we get,

(x)² + (2x+4)² = (2x+6)²

=> x² + 4x² + 16x + 16 = 4x² + 36 + 24x

=>x² + 4x² + 16x + 16 - 4x² - 36 - 24x = 0

=> (x²+4x²-4x²) + (16x-24x) + (16-36) = 0

=> x² - 8x - 20 = 0

=> x² - (10-2)x -20 = 0

=> x² - 10x +2x -20 = 0

=> x(x-10) + 2(x-10) = 0

=> (x-10)(x+2)= 0

therefore

either (x-10) = 0 ......or.......(x+2) = 0

either x = 10 ..........or ........ x = -2

as x, here is side and hence cannot be negative

therefore x = 10

smallest side = 10m

hypoteneus = 2x + 6 = 2(10)+6 = 26m

3rd side = (2x+4) = 2(10)+4 = 24m