Question

plzz.....solve this with step by step on.....copy I will mark one as brainlist...​

Answer 1

Answer:

HOPE it helps

Step-by-step explanation:

Answer 2

1) (a-b)(a-b)(a-b)

= a^2-ab-ab+b^2(a-b)

= a^2-2ab+b^2(a-b)

= a^3-2a^2b+b^2a-a^2b+2ab^2+b^3

=a³-3a²b+3ab²-b³

2) (a+b)^3-3ab(a+b)=a^3+b^3

3) a^3-b^3= (a+b)^3+3ab(a-b)

4) (a+b+c)(a+b+c)

= a^2+ab+ac+ab+b^2+bc+ac+bc+c^2

= a^2+b^2+c^2+2ab+2bc+2ac

5) a^3 + b^3 + c^3 - 3abc = (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc)

Adding 3abc both side

a^3 + b^3 + c^3 = (a + b + c)(a^2 + b^2 + c^2 - ab - ac - bc) + 3abc

Now, put a=x, b=y, and c=z

x^3 + y^3 + z^3 = (x + y + z)(x^2 + y^2 + z^2 - xy - xz - yz) + 3xyz

Put x+y+z =0 (Given)

x^3 + y^3 + z^3 = (0)(x^2 + y^2 + z^2 - xy - xz - yz) + 3xyz

x^3 + y^3 + z^3 = 0 + 3xyz

x^3 + y^3 + z^3 = 3xyz (Proved)

... pls mark as brainliest

(sry for late answer, was a big question)