Math, asked by sonyakhan9016, 1 year ago

Plzz tell me..... I will rate ur answer....
First - fill in the blank if two squares of side a CM are placed side by side then area of the resultant polygon will be______.
2 answer the following a rectangular piece of paper is 44 cm long and 20cm broad it is rolled along its length to form a cylinder find the volume of the cylinder so formed draw figure also
20cm long iron pipe has exterior diameter equal to 25 CM if the thickness of the pipe is 1 cm find the whole surface area of the pipe.
If anyone will give the answer of all these question I will mark her / him Brainliest


hukam0685: please mark this brainliest,, according to your promise

Answers

Answered by hukam0685
1

Answer:

1) \: 2 {a}^{2}  \:  {cm}^{2}  \\  \\ 2)1400 \:  {cm}^{3}  \\  \\ 3) \: 3168 {cm}^{2}  \\

Step-by-step explanation:

1)if two squares of side a CM are placed side by side then area of the resultant polygon will be______.

Ans: resultant polygon will be a rectangle, with length =2a

breadth = a

Area of rectangle =length×breadth

= 2a×a

2 {a}^{2}  \: sq-cm

2) A rectangular piece of paper is 44cmlong and 20cm broad it is rolled along its length to form a cylinder find the volume of the cylinder so formed draw figure also.

Ans: on rolling along its length,breadth will become perimeter of base and top of Cylinder

Perimeter of circle= 2πr

2\pi \: r = 20 \\  \\ r =  \frac{20}{2\pi}  \\  \\ r =  \frac{10}{\pi}  \\  \\

Volume of cylinder

 = \pi {r}^{2} h \\  \\  = \pi \times  \frac{10}{\pi}  \times  \frac{10}{\pi}  \times 44 \\  \\   = \frac{100 \times 7 \times 44}{22}  \\  \\  =  100 \times 7 \times 2 \\  \\  = 1400 \:  {cm}^{3}  \\  \\

3) 20cm long iron pipe has exterior diameter equal to 25 CM if the thickness of the pipe is 1 cm find the whole surface area of the pipe.

Ans:

Diameter external =25 cm

Radius , R=12.5 cm

Thickness = 1 cm

Internal diameter= 23 cm

Internal Radius ,r= 11.5 cm

length = 20 cm

Surface area of iron pipe:

 = 2\pi \: Rh + 2\pi \: rh + 2\pi( {R}^{2}  -  {r}^{2} ) \\  \\  = 2\pi(Rh \:  + rh +  {R}^{2}  -  {r}^{2} ) \\  \\  = 2 \times  \frac{22}{7} (12.5 \times 20 + 11.5 \times 20 + ( {12.5)}^{2}  - ( {11.5)}^{2} ) =  \frac{44}{7} (250 + 230 + 156.25 - 132.25) \\  \\  =  \frac{44}{7} (480 + 24) \\  \\  =  \frac{44}{7}  \times 504 \\  \\  = 72 \times 44 \\  \\  = 3168 \:  {cm}^{2}  \\  \\

Hope it helps you.

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