Plzz tell me the answer of this question with step by step.
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Grapes contains 80% and 20% actual ediable part
now we have 500 grams of grapes
so , 80 % of 500 = 80 × 500 / 100
= 400 grams of it as water
and remaining 100 grams as actual ediable part
now by removing water grapes turns to raisins
in this process only water throughs out and not actual part
so raisins contains 100 grams actual editable part .
but it is 80 % of weight of raisins
so , 100 grams --------- 80 %
?? grams --------- 100 %
weight of raisins = 100 × 100 / 80
weight of raisins = 125 grams
now we have 500 grams of grapes
so , 80 % of 500 = 80 × 500 / 100
= 400 grams of it as water
and remaining 100 grams as actual ediable part
now by removing water grapes turns to raisins
in this process only water throughs out and not actual part
so raisins contains 100 grams actual editable part .
but it is 80 % of weight of raisins
so , 100 grams --------- 80 %
?? grams --------- 100 %
weight of raisins = 100 × 100 / 80
weight of raisins = 125 grams
pravinsir:
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Answered by
0
Step-by-step explanation:
Grapes = 500 gm
Water = (80/100) * 500 = 400 gm
Other Weight = 500 - 400 = 100 gm
Let say Weight of resulted Resin = R gm
Water = (20/100)R = 0.2R
Other Weight = R - 0.2R = 0.8R
As only water is removed , other weight remains same
=> 0.8R = 100
=> R = 100/.8
=> R = 125
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