Math, asked by Afridiqus, 11 months ago

Plzz tell me the answer of this question with step by step.
If u solve it I will give u 40 points

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Answers

Answered by pravinsir
2
Grapes contains 80% and 20% actual ediable part

now we have 500 grams of grapes

so , 80 % of 500 = 80 × 500 / 100

= 400 grams of it as water

and remaining 100 grams as actual ediable part


now by removing water grapes turns to raisins

in this process only water throughs out and not actual part

so raisins contains 100 grams actual editable part .

but it is 80 % of weight of raisins

so , 100 grams --------- 80 %

?? grams --------- 100 %


weight of raisins = 100 × 100 / 80

weight of raisins = 125 grams

pravinsir: mark it as brainliest plz
Answered by humera98765
0

Step-by-step explanation:

Grapes = 500 gm

Water = (80/100) * 500 = 400 gm

Other Weight = 500 - 400 = 100 gm

Let say Weight of resulted Resin = R gm

Water = (20/100)R = 0.2R

Other Weight = R - 0.2R = 0.8R

As only water is removed , other weight remains same

=> 0.8R  = 100

=> R = 100/.8

=> R = 125

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