Question

plzz tell me this i will mark u as brainlist with full explanation

Answer 1

Step-by-step explanation:

Let the elements in both sets are:

A = {p,q,r,s,t}

B = {p,q,r,u}

We have, n(A) = 5, n(B) = 4

(i) n(A * B)

= n(A) * n(B)

= 5 * 4

= 20

(ii) n[(A * B) ∩ (B * A)]

(A * B) = (p,p),(p,q),(p,r),(p,u),(q,p),(q,q),(q,r),(q,u),(r,p),(r,q),(r,r),(r,u),(s,p),(s,q),(s,r),(s,u),(t,p),(t,q),(t,r),(t,u)

(B * A) = (p,p),(p,q),(p,r),(p,s),(p,t),(q,p),(q,q),(q,r),(q,s),(q,t),(r,p)(r,q),(r,r),(r,u),(r,t),(u,p),(u,q),(u,r),(u,s),(u,t)

∴ (A * B) ∩ (B * A) = {(p,p),(p,q),(p,r),(q,p),(q,q),(q,r),(r,p),(r,r),(r,u)}

Therefore, n[(A * B) ∩ (B * A)] = 9

Hope it help you!

Answer 2

n(A × B) = 5(4) = 20

n[(A × B) ∩ (B × A)] = 9

Step by step explanation:

Solution :

Given:

n(A) = 5 and n(B) = 4

Thus, we have:

n(A × B) = 5(4) = 20