plzz tell me this question
Attachments:
Answers
Answered by
1
duad first follow me then I'll give the correct answer
Answered by
1
In ΔACE,
62°+43° = exterior angle E
or ext. angle E = 105°
We know that in cyclic quadrilateral exterior angle is equal to interior opposite angle
Therefore In cyclic quad. ABDE
angle ABD(a) = ext. angle E = 105°
Again ext. angle D(c) = Angle A = 62°
Now in ΔDEF,
62° + 105° + angle DFE = 180° (since sum of 3 angles of Δ =180°
or angle DEF(b) = 13 °
Therefore a = 105° , b = 13° , and c =62°
62°+43° = exterior angle E
or ext. angle E = 105°
We know that in cyclic quadrilateral exterior angle is equal to interior opposite angle
Therefore In cyclic quad. ABDE
angle ABD(a) = ext. angle E = 105°
Again ext. angle D(c) = Angle A = 62°
Now in ΔDEF,
62° + 105° + angle DFE = 180° (since sum of 3 angles of Δ =180°
or angle DEF(b) = 13 °
Therefore a = 105° , b = 13° , and c =62°
YaminiRathi:
Plz mark this ans as brainlist answer
Similar questions