plzz tell ques no. 11
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Given 2x - 5y = 2.
On cubing both sides, we get
(2x - 5y)^3 = (2)^3
8x^3 - 125y^3 - 3 * 2x * 5y(2x - 5y) = 8
8x^3 - 125y^3 - 30xy(2) = 8
8x^3 - 125y^3 - 30 * 12 (2) = 8
8x^3 - 125y^3 - 720 = 8
8x^3 - 125y^3 = 720 + 8
8x^3 - 125y^3 = 728.
Hope this helps!
On cubing both sides, we get
(2x - 5y)^3 = (2)^3
8x^3 - 125y^3 - 3 * 2x * 5y(2x - 5y) = 8
8x^3 - 125y^3 - 30xy(2) = 8
8x^3 - 125y^3 - 30 * 12 (2) = 8
8x^3 - 125y^3 - 720 = 8
8x^3 - 125y^3 = 720 + 8
8x^3 - 125y^3 = 728.
Hope this helps!
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