Math, asked by vishist25, 10 months ago

plzz tell question 11

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Answered by yajmera8
0
let exam be of = x marks

A.T.Q,

paasing marks = 30% of x + 12

30/100×x + 12

3/10 x + 12 -(1)

paasing marks = 40% of x - 28

40/100 × x -28

4/10 x - 28 -(2)

By (1) and (2)

3/10 x + 12 = 4/10x - 28

3x+120/10 = 4x - 280/10

3x+120 = 4x - 280

x = 400

Total marks = 400

req. marks for passing = 30/100 × 400 + 12

=120+12

=132 marks

pass % required = 132/400×100=33 %

yajmera8: ha thats wht i wrote total marks = 400
yajmera8: and passing marks required are = 132
raj3778: Yes 400 132
vishist25: no (ii)wale me percentage puche gaye hai
raj3778: yess yr
yajmera8: likh die Bhai
vishist25: yes your answer was write
vishist25: thanks
yajmera8: hmm. just mark as brainliest
vishist25: kar diya
Answered by raj3778
0

Let the maximum marks be x.

30%of x+12 =40%of x-28

30x+1200=40x -2800

-10x =-4000

x=400marks

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