Question

Plzz tell the product.....

Answer 1

The product will be 2- methylprop 1-ene

Answer 2

Br is removed as HBr from the compound by KOH

to be preside alc.KOH

now there is a positive and negative charge on the carbon thus forming carbanion and carbocation

this leads to the formation of a double bond which results into

2-methypropene or 2-methylprop-1-ene

(see i have written it with proper IUPAC nomenclature)

(i am soo smart . LOL)

hope this helps