plzz tell the solution
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HEY FRIEND HERE'S YOUR ANSWER.
HOPE YOU FIND IT HELPFUL.
WITH CARE.
LB...... :-)
HOPE YOU FIND IT HELPFUL.
WITH CARE.
LB...... :-)
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rkdisha:
but the answer is 31.4×10^-8
i must have some mistake .ill check and let u know
and area of cross section is always in meter square
sry
Answered by
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Given:
l=1m
d=0.2mm → r=0.1mm
R=10Ω
By using the formula,
R= ρ౹/ A
= ρ౹/ πr²
Therefore, ρ= Rπr²/l
= 10× 3.14×( 0.1× 10⁻³)²/1
= 10× 3.14× 0.1×0.1× 10⁻⁶
= 0.314× 10⁻⁶
= 3.14× 10⁻⁷ Ωm
So resistivity = 3.14× 10⁻⁷ Ωm → 31.4× 10⁻⁸ Ωm
:) Hope this Helps !!!
l=1m
d=0.2mm → r=0.1mm
R=10Ω
By using the formula,
R= ρ౹/ A
= ρ౹/ πr²
Therefore, ρ= Rπr²/l
= 10× 3.14×( 0.1× 10⁻³)²/1
= 10× 3.14× 0.1×0.1× 10⁻⁶
= 0.314× 10⁻⁶
= 3.14× 10⁻⁷ Ωm
So resistivity = 3.14× 10⁻⁷ Ωm → 31.4× 10⁻⁸ Ωm
:) Hope this Helps !!!
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