Question

plzz tell this i will mark u as brainlist

Answer 1

RP=PQ
ANGLE RQP=75
ANGLE OQP=90
ANGLE OQR=15
DRAW PREPENDICULAR OQ ON SR(M)
IN TRIANGLE SQM AND QMR
SMQ=QMR(EACH90)
QM=QM(COMMON)
SM=MR(PREPENDICULAR FROM THE CENTRE BISECT THE CHORD)
TRIANGLE SMQ CONGRUENCE QMR(SAS)
SQ=SR(CPCT)
IN TRIANGLE SOQ AND ROQ
SQ=SR(PROVED ABOVE)
OQ=OQ(COMMON)
OS =OR(SAME RADII OF CIRCLE)
SOQ CONGRUENCE ROQ
ANGLE SQM=RQM
RQS=2OQS
RQS=2×15
RQS=30

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