Question

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Answer 1

Answer...

• SnCl2, Sn(||): [Xe]4d10 5s2
• SnCl2, Sn(||): [Xe]4d10 5s2SnCl4, Sn(|V): [Xe]4d10
• SnCl2, Sn(||): [Xe]4d10 5s2SnCl4, Sn(|V): [Xe]4d10Here with increase in oxidation state from Sn(||) to Sn(|V) the ionization potential of the central atom(here Sn) increases this makes the Sn-Cl bonds more covalent in SnCl4 compared to SnCl2- Fajan’s rules.
• SnCl2, Sn(||): [Xe]4d10 5s2SnCl4, Sn(|V): [Xe]4d10Here with increase in oxidation state from Sn(||) to Sn(|V) the ionization potential of the central atom(here Sn) increases this makes the Sn-Cl bonds more covalent in SnCl4 compared to SnCl2- Fajan’s rules.Hence the SnCl2 molecules due greater ionic character are closely packed* whereas in SnCl4 the molecules show weaker London forces of interaction due covalent nature.
• SnCl2, Sn(||): [Xe]4d10 5s2SnCl4, Sn(|V): [Xe]4d10Here with increase in oxidation state from Sn(||) to Sn(|V) the ionization potential of the central atom(here Sn) increases this makes the Sn-Cl bonds more covalent in SnCl4 compared to SnCl2- Fajan’s rules.Hence the SnCl2 molecules due greater ionic character are closely packed* whereas in SnCl4 the molecules show weaker London forces of interaction due covalent nature.Thus explains the given observation.
• SnCl2, Sn(||): [Xe]4d10 5s2SnCl4, Sn(|V): [Xe]4d10Here with increase in oxidation state from Sn(||) to Sn(|V) the ionization potential of the central atom(here Sn) increases this makes the Sn-Cl bonds more covalent in SnCl4 compared to SnCl2- Fajan’s rules.Hence the SnCl2 molecules due greater ionic character are closely packed* whereas in SnCl4 the molecules show weaker London forces of interaction due covalent nature.Thus explains the given observation.*SnCl2 is observed to form Chloride bridges thus forming closely packed crystalline solid. Such chains are not observed in SnCl4

Answer 2

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