Question

plzz telll the ans.

Answer 1

hope this helps you......

Answer 2

a= (3+√5)/2
1/a = 1/[(3+√5)/2]

=> 1/a = 2/(3+√5) 

=> 1/a = 2(3-√5)/(3+√5)(3-√5)
rationalizing the denominator

=> 1/a = (6-2√5)/3²-(√5)²
=> 1/a = (6-2√5)/9-5 
=> 1/a = (6-2√5)/4 


(a+1/a)² = a²+1/a ²+2
{(x + y)}^{2} = {x}^{2} + {y}^{2} + 2xy(x+y)​2​​=x​2​​+y​2​​+2xy 

=> [(3+√5)/2 + (6-2√5)/4] = a²+1/a²+2

=> [2(3+√5)/(2)2 + (6-2√5)/4] = a²+1/a²+2
Making denominator equal


=> (6+2√5+6-2√5)/4 = a²+1/a²+2
=> 12/4 = a²+1/a²+2

=> 3 = a²+1/a²+2

=> 3-2 = a²+1/a²

=> 1 = a²+1/a²


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