Question

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Answer 1

therefore total resistance is 3Ω

Answer 2

in parallel combination...
$\frac{1}{3} + \frac{1}{2} + \frac{1}{6} = \frac{1}{r}$
$\frac{2 + 3 + 1}{6} = \frac{1}{r}$
$\frac{6}{6} = \frac{1}{r}$
therefore....

$r = 1 \: ohm$
total resistance (in series combination)now.... .

R=[1+1+1]ohm=3 ohm


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