Question

plzzźzzzźź answer it

Answer 1

x'2 - 4x -3x +12 =0
x (x-4) -3 (x-4) =0
(x-3) (x-4) =0

x =  3 ; 4

Answer 2

$x {}^{2} - 4x - 3x + 12 = 0 \\ x (x- 4) - 3(x - 4) \\ x = 3 \: and \: \: x = 4$