plzzz ans......CONGRUENCCE OF TRIANGLES......ANS ALL PARTS
Attachments:
Answers
Answered by
3
In triangle BLD and CMD
i) Angle BLD = angle CMD (both are 90°)
ii) BL = CM ( given)
iii) Angle BDL = angle CDM (as they are vertically opposite angles)
So, we can say triangle BLD and CMD are congruent
So,
BD = CD ( by C.P.C.T)
As BC is being dividend into two equal parts by AD in triangle ABC, then AD must be the median of traingle ABC.
i) Angle BLD = angle CMD (both are 90°)
ii) BL = CM ( given)
iii) Angle BDL = angle CDM (as they are vertically opposite angles)
So, we can say triangle BLD and CMD are congruent
So,
BD = CD ( by C.P.C.T)
As BC is being dividend into two equal parts by AD in triangle ABC, then AD must be the median of traingle ABC.
Answered by
0
TO PROVE= AD is a median
or, AD bisects BC
or, BD = DC
In triangle BLD & triangle CMD. :-
1.Angle BLD = Angle CMD. (90°)
2.BL = CM. ( GIVEN)
3. Angle BDL = Angle CDM ( VERTICALLY OPPOSITE ANGLE )
therefore triangle BLD CONGRUENT triangle CMD
hence , BD = CD ( CPCT)
or, AD bisects BC
or, BD = DC
In triangle BLD & triangle CMD. :-
1.Angle BLD = Angle CMD. (90°)
2.BL = CM. ( GIVEN)
3. Angle BDL = Angle CDM ( VERTICALLY OPPOSITE ANGLE )
therefore triangle BLD CONGRUENT triangle CMD
hence , BD = CD ( CPCT)
ayushkumar17:
plz mark as brainliest
Similar questions