plzzz ans.......CONGRUENCE OF TRIANGLES.......ANS ALL PARTSSS
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In trianlge TXQ & triangle SXQ :-
1. angle XSQ = angle XTQ ( 90°)
2. angle XQS = angle SQT ( SINCE QX is bisector of angle Q )
3.QX = QX ( COMMON)
i.THEREFORE, TXQ congruent SXQ ( BY AAS)
HENCE, angle TXQ = angle SXQ( CPCT)....equation 1.
ii. construction:-
draw XU perpendicular PR.
SIMILARLY , PROVE THAT TRIANGLE PXT CONGRUENT TRIANGLE PXU ( BY ASA)
HENCE , ANGLE XPT = ANGLE XPU ( CPCT)
THEREFORE PX BISECT ANGLE P
1. angle XSQ = angle XTQ ( 90°)
2. angle XQS = angle SQT ( SINCE QX is bisector of angle Q )
3.QX = QX ( COMMON)
i.THEREFORE, TXQ congruent SXQ ( BY AAS)
HENCE, angle TXQ = angle SXQ( CPCT)....equation 1.
ii. construction:-
draw XU perpendicular PR.
SIMILARLY , PROVE THAT TRIANGLE PXT CONGRUENT TRIANGLE PXU ( BY ASA)
HENCE , ANGLE XPT = ANGLE XPU ( CPCT)
THEREFORE PX BISECT ANGLE P
sanj2:
how u proved congruence between triangle PXT AND PXU
px = px(common) , ptx = pux(90) & pxt = pxu ( due to given figure)
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