Question

plzzz ans.......CONGRUENCE OF TRIANGLES.......ANS ALL PARTSSS

Answer 1

See the ans in attach file

Answer 2

In trianlge TXQ & triangle SXQ :-
1. angle XSQ = angle XTQ ( 90°)
2. angle XQS = angle SQT ( SINCE QX is bisector of angle Q )
3.QX = QX ( COMMON)

i.THEREFORE, TXQ congruent SXQ ( BY AAS)
HENCE, angle TXQ = angle SXQ( CPCT)....equation 1.

ii. construction:-
draw XU perpendicular PR.
SIMILARLY , PROVE THAT TRIANGLE PXT CONGRUENT TRIANGLE PXU ( BY ASA)
HENCE , ANGLE XPT = ANGLE XPU ( CPCT)
THEREFORE PX BISECT ANGLE P