Question

plzzz ans.....Indices......Thnk u

Answer 1

hope its help you and my steps amd answer are correct

Answer 2

Hey there!

(27^ 2n/3 ✖ 8 ^ -n /6) /18^ -n/2

[3^3(2n/3) ✖ 2^ 3( -n/6) ] / (2*9) ^ -n/2

[3^2n ✖ 2^ -n/2 ] / 2^ -n/2 * 9^ -n/2

3^ 2n / 9^ -n/2

3^2n / 3^ -n

3^ 2n - (-n)

3^3n

27^ n

The required answer is 3^ 3 n or 27ⁿ

hope helped!