Question

plzzz ans it ...fast...

Answer 1

Here is your solution :

Let the ones place digit is z.

Tens place is y.

Hundreds place is x.

Number = 100x + 10y + z

A/Q,

=> Sum of digits = 12

=> x + y + z = 12 -------- ( 1 )

And,

=> 100x + 10y + z + 495 = 100z + 10y + x

=> 100x - x + 10y - 10y + z - 100z + 495 = 0

=> 99x - 99z + 495 = 0

=> 495 = 99z - 99x

=> 495 = 99( z - x )

=> ( z - x ) = 495 ÷ 99

=> ( z - x ) = 5

=> x = z - 5 -------- ( 2 )

And,

=> 100x + 10y + z + 36 = 100x + 10z + y

=> 100x - 100x + 10y - y + z - 10z + 36 = 0

=> 9y - 9z - 36 = 0

=> 9z - 9y = 36

=> 9( z - y ) = 36

=> ( z - y ) = 36 ÷ 9

=> ( z - y ) = 4

•°• y = z - 4 ----------- ( 3 )

Substitute the value of ( 2 ) and ( 3 ) in ( 1 ),

=> x + y + z = 12

=> z - 5 + z - 4 + z = 12

=> 3z - 9 = 12

=> 3z = 12 + 9

=> 3z = 21

=> z = 21 ÷ 3

•°• z = 7

Substitute the value of z in ( 2 ),

=> x = z - 5

=> x = 7 - 5

•°• x = 2

Substitute the value of z in ( 3 ),

=> y = z - 4

=> y = 7 - 4

•°• y = 3

Now we have,

x = 2 , y = 3 and z = 7

So number = 100x + 10y + z

= ( 100 × 2 ) + ( 10 × 3 ) + 7

= 200 + 30 + 7

= 237

Option c. ) 237.