plzzz ans....logarithms...solve for X ....thnk u
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log(10x + 5) - log(x -4) = 2
we know ,
logm - logn = log( m/n )
use this concept here,
log{( 10x + 5)/( x -4) } = 2
we also know,
log{ x base a } = N
x = a^N
use this concept now ,
(10x + 5)/(x -4) = 10²
10x + 5 = 100(x -4)
10x + 5 = 100x -400
-90x = -405
x = 405/90
we know ,
logm - logn = log( m/n )
use this concept here,
log{( 10x + 5)/( x -4) } = 2
we also know,
log{ x base a } = N
x = a^N
use this concept now ,
(10x + 5)/(x -4) = 10²
10x + 5 = 100(x -4)
10x + 5 = 100x -400
-90x = -405
x = 405/90
sanj2:
10^2 came how?????
log a means log a base 10
okk
plzx solve my other log problems tooo☺
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