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if the perimeter of a square is 40cm then the length of each side is 10cm
so AC²+BD² is 100 +100
=200cm²
so AC²+BD² is 100 +100
=200cm²
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Given Perimeter of a Square ABCD = 40cm
Required to find= AC^2 + BD^2
we know that... Perimeter of a Square = 4s
(s = side) ..
40cm = 4s
40cm/4 = s
10cm = s...so each side of this Square = 10 cm....
We know that all sides , diagonals of a Square are equal so...
AB = BC = CD = DA = AC = BD
so..all are equal to 10 cm...
So
= AC^2 + BD^2
= 10^2 + 10^2
= 100 + 100
= 200
Required to find= AC^2 + BD^2
we know that... Perimeter of a Square = 4s
(s = side) ..
40cm = 4s
40cm/4 = s
10cm = s...so each side of this Square = 10 cm....
We know that all sides , diagonals of a Square are equal so...
AB = BC = CD = DA = AC = BD
so..all are equal to 10 cm...
So
= AC^2 + BD^2
= 10^2 + 10^2
= 100 + 100
= 200
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