plzzz ans.....Mensuration.....TRIANGLE....QUESTION NO. 14
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Please mark brainliest.
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Area =60cm^2
We know that area of a triangle = 1/2*base*height
ATQ
1/2*(x+1)(x+2)=60
Therefore x=7
So, AB=15cm
BC=8
Therefore AC^2=AB^2+BC^2(by Pythagoras theory)
So AC=17
Therefore perimeter =(17+15+8)cm
=40cm
The perimeter of the triangle =40cm
We know that area of a triangle = 1/2*base*height
ATQ
1/2*(x+1)(x+2)=60
Therefore x=7
So, AB=15cm
BC=8
Therefore AC^2=AB^2+BC^2(by Pythagoras theory)
So AC=17
Therefore perimeter =(17+15+8)cm
=40cm
The perimeter of the triangle =40cm
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