plzzz ans....Quadratic equation....Thnx
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Let the length be xm
& breadth be ym
then,
according to question,
perimeter of Rectangle=2(l+b)
180=2(x+y)
180=2x+2y
dividing both sides from 2
90=x+y
since we have to take value of y in terms of x as asking in the question,
x+y=90
y=90-x
so, breadth comes to be 90-x
now,
area of Rectangle=length×breadth
1800=xy
1800=x(90-x)
1800=90x-x²
x²-90x+1800=0
x²-30x-60x+1800=0
x(x-30)-60(x-30)=0
(x-30)(x-60)=0
(x-30)=0
x=30
(x-60)=0
x=60
*If length is 30m
then breadth =90-x
=90-30
breadth=60m
*If length is 60m
then breadth=90-x
=90-60
breadth=30m
@Altaf
& breadth be ym
then,
according to question,
perimeter of Rectangle=2(l+b)
180=2(x+y)
180=2x+2y
dividing both sides from 2
90=x+y
since we have to take value of y in terms of x as asking in the question,
x+y=90
y=90-x
so, breadth comes to be 90-x
now,
area of Rectangle=length×breadth
1800=xy
1800=x(90-x)
1800=90x-x²
x²-90x+1800=0
x²-30x-60x+1800=0
x(x-30)-60(x-30)=0
(x-30)(x-60)=0
(x-30)=0
x=30
(x-60)=0
x=60
*If length is 30m
then breadth =90-x
=90-30
breadth=60m
*If length is 60m
then breadth=90-x
=90-60
breadth=30m
@Altaf
Radhika411:
Thnx dude
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